Determining Wind Turbine Annual Power Output - a Simple Formula Based Upon Blade Diameter and Average Wind Speed at Your Location
Are you looking to lower your electric bills by using wind power as alternative energy? You're not the only one, millions of people are looking into going green. Moving into wind power will reduce your carbon footprint thus helping the environment and will reduce your energy costs and dependence on foreign oil.
If you're looking into wind power you probably want to know how much power a home wind generator actually produces. In order to determine a realistic approximation of what power can be generated on your property there are some rules and guidelines that you can use.
To determine the approximate annual energy output for a small wind turbine, you can use the following formula:
(Yearly output in kilowatt-hours) = (0.01328) x (blade diameter in
feet) 2 x (average wind speed in miles per hour at your location) 3
The simplified formula is: Power = 0.01328(D) 2(V) 3
There are two factors that have a significant impact on energy output, blade diameter and wind speed. Increasing the blade diameter increases the energy output as a square function. For instance, if you increase the blade diameter by a factor of 2, the energy output will increase 4-fold.
Although blade diameter has a dramatic impact on energy output, wind speed is even more important. Energy is a cubic function of wind speed. For example, if wind speed is doubled, the energy output will increase by a factor of 8. Thus, wind speed is the most important consideration in smaller wind turbine energy production.
The above equation and discussion therefore indicates that your money is better spent on raising the height of your tower or choosing a better location with greater wind exposure than on a generator with larger diameter blades.
Having been involved in the alternative energy field for over 20 years, D. R. Smith has done a large amount of research and testing of various designs and found what he believes are the best energy generator plans currently available. He's also put together some alternative energy reviews to help you make the best choice when building your wind and solar power system. You can read them here: http://www.powerplans.net
Article Source: ArticlesBase.com
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can you give me some problem to be solve in potential enrgy and power?
formula for potential enrgy: PE=mgh
formula for power: P=work/time
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Horse power question- pumping water?
At what rate can a half-horsepower well pump deliver water to a tank 80m above the water level in the well? Give your answer in kg/s. (hp= 746J/s ).
Please help me set up this problem. I have been working on it for quite a while and haven't figured it out. I have tried using the formulas for power, work and force but haven't gotten it quite right. thanks!!
Thats the right answer! Thank you so much :)
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What is the formula for power?
Please don't just say letters or whatever tell me what it is. For example I think it may be force(distance) divided by time in seconds but i'm not certain and I don't need a bunch of F(x)/T type answers. Thanks.
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power loss is also equals to V*V/R, so, when the voltage is high, power loss should be high. but not??? why??
i mean, why do we only consider I*I*R as a formula for power loss but not V*V/R. according to power , both the formulas represent the power loss. thank you in advance for the answers.
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2 phase power formula?
Since formula for power in 3 phase power systems is P = 1.732xVphaseXIphase. What is the formula for power in 2 phase systems?
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How Capacitor Banks Should Be Wired In Order To Improve Power Factor?
I know that when trying to improve power factor capacitor banks should be inserted, but not knowing what the best solution is wired in Series OR Parallell?? Also what the formula for Power Factor is and what power factor loosage is acceptable in the United Kingdom,beacause in places i have heard that 0.8ohms is the maximum is this true. Please bare with me as i am new to PF and also Yahoo Answers Thanks for your help and support in advance!!!
Thanks for the replies guys much appreciated, the reasoning behind these questions are that i have an exam and was not too clear on this subject. "poorone" you say that if there is too many capacitors inserted that there would be a leading current, is this true for both a.c and d.c supplies? because i have a question paper stating "When a series circuit containing resistance and capacitive reactance is connected to an a.c supply the current will
a) be in phase with the voltage
b) lag the voltage
c) lead the voltage
d) appose the voltage
I have come to know that the correct answer is C to lead the voltage, but not knowing the reasoning behind this and would this also be true for a parallell circuit or would that appose the voltage??
Again thanks for your replies much appreciated!!
"Thomas C" you are right in suggesting 0.80 power factor or better it was just my own mistake of not being too clear about what i wanted to state sorry but thanks for your reply! and look forward to using that calulator
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Jesus gave us a formula for power in living, what was it?
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